How many moles of HCl are required to neutralize all 0.050 mol of Ca(OH)2 if ).050 mol of Ca(OH)2 are combined with 0.080 mol of HCL according to the following equation Ca(OH)2+2HCl - CaCl2+2H2O

Question

How many moles of HCl are required to neutralize all 0.050 mol of Ca(OH)2 if ).050 mol of Ca(OH)2 are combined with 0.080 mol of HCL according to the following equation Ca(OH)2+2HCl -> CaCl2+2H2O

anonymous · Answer

@aaronq

anonymous · Answer

@freethinker

anonymous · Answer

according to the equation, in what number ratio should calcium hydroxide and HCl react?

anonymous · Answer

1:2 ?

anonymous · Answer

i agree. so what do you think? how many mols of HCl do we need to react with all of the Ca(OH)2?

anonymous · Answer

2, in that simple equation. But there was a given of, 0.050 mol of Ca(OH)2 and 0.080 mol of HCl.

anonymous · Answer

Would I just multiply 0.080 by 2?

anonymous · Answer

hmm...what makes you decide to choose the number of HCl (and not the number of hydroxide?