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Chemistry 16 Online
OpenStudy (anonymous):

What would be the pH of a 0.065M solution of HBr?

OpenStudy (abb0t):

pH = -log\([H^+]\)

OpenStudy (anonymous):

the (H+) is 0.065M right?

OpenStudy (abb0t):

\([H^+]\)*

OpenStudy (anonymous):

right but 0.065M is the [H+] right?

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