Question

Could someone please help me out with this problem please

Answer 1

@satellite73 can you please help me

Answer 2

@smokeydabear can you help me figure this problem out please

Answer 3

@Callisto can you please help me out

Answer 4

@KingGeorg could you help me with a problem

Answer 5

@KingGeorge could you please help me with this problem

Answer 6

can you help me

Answer 7

@electrokid can you please help me

Answer 8

so, we first have to find its derivative

Answer 9

ok

Answer 10

so, what do you get for the derivative?
notice that you wil have to use the product rule here since there are two things multiplying eachother

Answer 11

I am not familiar with the product rule we have only learned the chain rule so far

Answer 12

we are justbeginning to learn how to do the chain rule so do you mind walking me through it

Answer 13

\[
{d\over dx}(u\cdot v)=u'v+uv'
\]

Answer 14

in this problem, you have
\[x\cdot e^{2x}\]

Answer 15

ok yup I am following

Answer 16

now, apply the formula I showed above

Answer 17

it would be x v+u e^2x

Answer 18

well, when I said that, I meant
\[u=x\\v =e^{2x}\\
{d\over dx}(xe^{2x})={d\over dx}(x)e^{2x}+x{d\over dx}(e^{2x})
\]kapeesh?

Answer 19

oh I put them in the form when you did the v'u thing

Answer 20

I got what you mean though

Answer 21

yep
all you gotta do is simplify that

Answer 22

x^2(e2x)

Answer 23

? lets see your steps ?

Answer 24

and use the equation editor, will ya

Answer 25

I took the x's and combined to make x^2 then I combined e^2x oh that should be e^4x

Answer 26

? no no wayy off there

Answer 27

I amconfussed then

Answer 28

steps:
look at what I wrote, derivative of "x" times \(e^{2x}\) + x times derivative of \(e^{2x}\)

Answer 29

ok

Answer 30

ok then what