Question

write an equation in slope intercept form of the line that passes through these points: (3,-2)(6,1)

**explain

Answer 1

no help

Answer 2

first you need the slope of the line

Answer 3

points are (3,-2), (6,1)

from 3 to 6 is right 3 units, from -2 to 1 is up 3 units
right 3, up 3, slope is \(\frac{3}{3}=1\)

Answer 4

you can also compute via
\[m=\frac{y_2-y_1}{x_2-x_1}=\frac{1+2}{6-3}=\frac{3}{3}=1\] if you like

Answer 5

then write in "point slope form"\[y-y_1=m(x-x_1)\] in your case you have
\[y-1=1(x-6)\] or just
\[y-1=x-6\] add 1 to solve for \(y\) and get
\[y=x-5\]

Answer 6

@satellite73 why did you do "1+2" if its y2-y1?

Answer 7

good point
\[\frac{1-(-2)}{6-3}\] might have made it clearer
i skipped that step

Answer 8

oh ok

Answer 9

wouldn't your y-y1 be
y-(-2)? @satellite73

Answer 10

nevermind you did y1 for the second points

Answer 11

once you have the slope, you can use either point

Answer 12

right
try it with the other point and you will see you get the same equation
doesn't matter which one you use