Question

Find the fourth term in the expansion of (3x-y^2)^6.

Answer 1

The fourth term is 20a^3 b^3. Substituting in a=3x and b=-y^2, this is
20(3x)^3 (-y^2)^3
= -20*3^3*x^3*y^6
= -540 x^3 y^6

Answer 2

im confused on what my answer will be. @wmckinely

Answer 3

nvm i got it..