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Mathematics 15 Online
OpenStudy (anonymous):

can someone help me with this triangle problem??? Thanks

OpenStudy (anonymous):

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OpenStudy (anonymous):

what's the question ?

OpenStudy (anonymous):

I attached it

OpenStudy (anonymous):

I need to solve for x,y and z

OpenStudy (jdoe0001):

can you give us a screenshot of it?

OpenStudy (anonymous):

OpenStudy (jdoe0001):

lol

OpenStudy (jdoe0001):

I meant, a screenshot of the actual paper/material, somehow you seem to be missing some things

OpenStudy (anonymous):

no thats it. Its not on my computer, just a worksheet. There are no directions, it just says solve for x, y and x

OpenStudy (anonymous):

I have no idea what to do. I tried to use side/altitude= altitude/ other side but it didnt work

OpenStudy (raden):

first, to get the value of x, take this equation : (x+2)^2 = x(x+x+1) solve for x

OpenStudy (anonymous):

ok thanks... let me do it out

OpenStudy (anonymous):

once you find x use this eq y=1/2(x+x+1) to solve for y

OpenStudy (anonymous):

where do I go from 4=x^2+x

OpenStudy (raden):

(x+2)^2 = x(x+x+1) you have to simplify it,can u ?

OpenStudy (anonymous):

square root of 3?

OpenStudy (raden):

(x+2)^2 = x(x+x+1) expand the term in left side, also simplify the terms in right side x^2 + 4x + 4 = x(2x+1) x^2 + 4x + 4 = 2x^2+x after simplify, now we have x^2 - 3x - 4 = 0

OpenStudy (anonymous):

wouldn't it just be x^2+2^2=x^2+x^2+1

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