Question

dy/dx = 1/x^2 + x, x>0,y(2) = 1

Answer 1

this looks like a separable equation, what class is it?

Answer 2

calculus

Answer 3

ok it looks like your going to have to integrate here because you only have the value for y

Answer 4

yeah i know i got y = -1/x + x^2/2 + c

Answer 5

then i just make y 2 and set it to 0?

Answer 6

close. you have value for y and x, find c

Answer 7

y(2)=1, if y=1, what does x =?

Answer 8

1? not sure what u mean

Answer 9

if your given a function, f(x)=2x, what is f(3)

Answer 10

6

Answer 11

Sweet, so whats x?

Answer 12

2

Answer 13

aw close its 2*x but x isnt 2, x is what use put in the function to find 6

Answer 14

-1/2 and 2?

Answer 15

oh that ffuction would be 3

Answer 16

thought u were talking about the first

Answer 17

nice then whats y and x in y(2)=1

Answer 18

-1/x + x^2/2 + c ?

Answer 19

ok dude if y=1 and x=2, and y=-1/x+x^2/2+c, find "c"

Answer 20

did u see my first comment u,y

Answer 21

where is it?

Answer 22

2nd and 3rd comment

Answer 23

ok but y isnt 2 its 1 and x is 2, and you need to find c

Answer 24

-1/x+x^2/2-1/2, there you go buddy. c is -1/2 according to your integration.