Question

factor: 6t^2-t-15

Answer 1

Oops . 7t(t-4) ??

Answer 2

Hi,batman.

Answer 3

No, that would multiply to 7t² - 28t.
Have you learned the quadratic equation yet?

Answer 4

(2t+3)(3t-5)

Answer 5

@ladyrosebud how do you figure it out?

Answer 6

yeah @ladyrosebud is correct

Answer 7

I made an error :( its 7t^2-28t

Answer 8

7t(t-4)

Answer 9

Ok can I help?

Answer 10

Yes, thats what I thought

Answer 11

it's (t-5/3)(t+3/2)

Answer 12

We can do this using a method called "Product - Sum" Method

The standard form of a Quadratic Function is \[Ax ^{2} + Bx + C\]

We have to find two numbers such that their Product is A.C and their Sum is B

In the given function \[6t ^{2}-t-15\]
A = 6; B = -1 and C = -15

I have to find two numbers that I multiply should give me -90 and add them should give me -1.

So Product is 6 x -15 = -90

Sum is -1



Now set up a table like this and list all product pairs for -90.