Question

The population of a town was 6,000 in 1990 and grew to 9,000 in 2000. Assume that the population will continue to grow exponentially at the same rate. What will the population of the town be in 2010? Please help :O

Answer 1

this is an exponential growth problems. just use the equation for exponential growth

Answer 2

What is the equation?

Answer 3

something like y = a(1 + b)x ?

Answer 4

A(t))=Ainitial*e^k*t

Answer 5

How do I figure out the rate of growth? Will you write a key corresponding the the letters in the equation as you typed it?

Answer 6

A initial is 6000, A(t) 9000, e is constant 2.71..., k is a variable you find, t is the change it time( subtract final year minus initial)

Answer 7

would you lke me to solve?

Answer 8

So.. 9000=6000*2.71^k*20 and solve for k? Lol, sorry I'm so slow.. that isn't right is it?

Answer 9

yes

Answer 10

k=-2.5982 so now I just plug that back in for k?

Answer 11

now read the question again

Answer 12

I don't understand.

Answer 13

the question asks for the population in 2010, now you have to find final population A,
A intial can be 6000 or 9000, time would be (2010 - intial time(depends on which initial value you use)) and you have k, solve A in A=Aintial*e^kt

Answer 14

ah okay

Answer 15

a=9000*2.71^(-2.5982*20)

Answer 16

there only errors now are math ones ^^.

Answer 17

I'm getting weird answers form my calculator...

Answer 18

value?

Answer 19

my k is .000152

Answer 20

sry its .1046

Answer 21

i get 48665 what do u get?

Answer 22

hah, 9027, fml

Answer 23

maybe i should look at it again in the morning

Answer 24

yeah rest ez man

Answer 25

Thanks bro