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Mathematics 12 Online
OpenStudy (anonymous):

How many roots do the following equations have? -12x2 - 25x + 5 + x3 = 0 A. 2 B. 3 C. 4 D. 5

OpenStudy (anonymous):

@rajee_sam @Numb3r1

OpenStudy (anonymous):

An equation can have up to as many roots as its degree (highest power of x) so 4 and 5 are out.

OpenStudy (rajee_sam):

For the no. of roots you have to look at the highest degree of the function. Here it is 3 so it will have 3 roots

OpenStudy (anonymous):

Not necessarily. If there's a quadratic factor without real roots you'll only have two.

OpenStudy (rajee_sam):

It is only asking how many roots it will have. It will have 3 roots all real and complex put together.

OpenStudy (dan815):

ok

OpenStudy (anonymous):

True.

OpenStudy (anonymous):

so 3

OpenStudy (rajee_sam):

yes

OpenStudy (anonymous):

thank you all :)

OpenStudy (rajee_sam):

No. of roots = Highest degree of the polynomial. If they are asking how many real and complex you cannot say that by just looking. you have to factorize and see then

OpenStudy (dan815):

buutt x^2 +1 = 0 roots!

OpenStudy (dan815):

x^3 has only 1 root, a repeating root

OpenStudy (rajee_sam):

0 real roots

OpenStudy (anonymous):

but it asks only about roots in general not just the real

OpenStudy (rajee_sam):

for x^3 you say one root but multiplicity 3 so three roots

OpenStudy (anonymous):

How many roots do the following equations have? -12x2 - 25x + 5 + x3 = 0 A. 2 B. 3 C. 4 D. 5

OpenStudy (rajee_sam):

yes @malkassir

OpenStudy (anonymous):

so 3

OpenStudy (rajee_sam):

yes

OpenStudy (dan815):

ok i see, then 3 indeed, just checking because, they can actually be asking you to do some work and see that, that equation really does have 3 real roots

OpenStudy (anonymous):

yupe okay I posted a new question plz check it out

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