Question

walk me through how 2 solve this please

Answer 1

\[\frac{ 8 }{ x }+\frac{ 15 }{ x ^{2} }=-1\]

Answer 2

multiply everithing by x^2

Answer 3

every term by x^2

Answer 4

the numerators 2?

Answer 5

yes

Answer 6

then what?

Answer 7

@ajprincess ............

Answer 8

\[x^2*\frac{8}{x}+x^2*\frac{15}{x^2}=-1*x^2\]

Answer 9

what do u do after that?

Answer 10

\[x*\cancel x*\frac{8}{\cancel x}+\cancel x^2*\frac{15}{x^2}=-x^2\]
\[8x+15=-x^2\]

Answer 11

getting this?

Answer 12

\(8x+15=-x^2\)
\(8x+15+x^2=0\)
\(x^2+8x+15=0\)
Nw let us use the quadratic formula to find x.
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 13

Compare the equation \(x^2+8x+15=0\) with \(ax^2+bx+c=0\) nd cam u tell me the values of a, b and c?

Answer 14

yeah a=0 b=8 c=15

Answer 15

b nd c r right. pls check a.

Answer 16

1?

Answer 17

yup:)

Answer 18

Nw can u find x?

Answer 19

ill try, 1 sec

Answer 20

ok. take ur time:)

Answer 21

-8?

Answer 22

nope:(

Answer 23

\[x=\frac{-8\pm\sqrt{8^2-(4*1*15)}}{2*1}\]

Answer 24

if u dnt mind can u pls make it a bit clear?

Answer 25

untill the last part i was simplifying the sq root. i got 2 and then added the -8 +- and the devide by 2, making it -8(-+) 2/2 i thought the 2's cancle each other out making it 8

Answer 26

*-8

Answer 27

nope.
this is what u get finally right
\[x=\frac{-8\pm2}{2}\]
that is
\(\Large{ x=\frac{-8+2}{2}}\) or \(\Large{ x=\frac{-8-2}{2}}\)
first u need to simplify the numerator.

Answer 28

ok -6 or -10?

Answer 29

those are ur numerators right?

Answer 30

i think so.........

Answer 31

\[x=\frac{-8+2}{2}=\frac{-6}{2}=?\]

Answer 32

-6/2= -3 -5?

Answer 33

-6/2=-3? or -5?

Answer 34

@janeDoe100

Answer 35

-3

Answer 36

all of the answers on my paper have 3 and 5 in it. how?

Answer 37

-3 is right:)
Nw tell me what is
\[x=\frac{-8-2}{2}=\frac{-10}{2}=?\]

Answer 38

-5

Answer 39

ya right:)
so ur x values are -3 and -5. tell me the options given to u?

Answer 40

-3 and -5 is b :D

Answer 41

:)