The figure below shows line AB parallel to line CD. Segment EF is parallel to segment GH.
What is the value of x?

Question

The figure below shows line AB parallel to line CD. Segment EF is parallel to segment GH. 
What is the value of x?

anonymous · Answer

attachment

anonymous · Answer

@.Sam. @ganeshie8

ganeshie8 · Answer

$\angle GEF $ and $\angle BGH$ are corresponding angles, so they're congruent.

$\angle GEF \cong \angle BGH$

anonymous · Answer

okay to set up the problem would it be 2x-60=x+5

ganeshie8 · Answer

correct !

since $\angle GEF$ and $\angle EFC$ are alternate interior angles, they're congruent.

 $\angle GEF \cong \angle EFC$

 $2x-60 = x+5$

 solve x

anonymous · Answer

I think I did it wrong :c I got -27.5

ivettef365 · Answer

Both angles are the same therefore x+5 = 2x-60
therefore, x=65

anonymous · Answer

how do you get that though? you just add the 5 to the 60

ivettef365 · Answer

You combine like terms:  the 2x - x = 60 + 5

ganeshie8 · Answer

you have 

$2x-60 = x + 5$

ganeshie8 · Answer

first step, subtract x from both sides

ivettef365 · Answer

x + 5 = 2x - 60
-x           -x
-----------------
         5  = x - 60
     +60        +60
=============
      65  = x

ganeshie8 · Answer

$2x-60 = x + 5$

$x-60 =  5$

ganeshie8 · Answer

second step, add 60 to both sides

ganeshie8 · Answer

$2x-60 = x + 5$

$x-60 =  5$

$x =  65$

anonymous · Answer

oh!! I was doing it completely different, thanks guys :)

ganeshie8 · Answer

thats it, 2 step equation it is

anonymous · Answer

thanks @ivettef365 , and ganeshie !

ganeshie8 · Answer

np, yw :)