Question

Write an equation for the line that passes through the points (0, -2) and (-4, 0).


y= -2x- 4
y= -2x- 2
y= -1/2x - 2
y= -1/2x - 4

Answer 1

@iheartfood is that the same??

Answer 2

The equation of the line is y=mx+b

Answer 3

y= -(1/2)x-2

Answer 4

point slope form:\[(y-y_1)=m(x-x_1)\]
formula for slope:\[m={{y_2-y_1}\over{x_2-x_1}}\]
equation of a line:\[y=mx+b\]

Answer 5

Find the slope an substitute for m, you already have b = -2

Answer 6

Let the equation be
y=mx+c
\[m=\frac{y_2-y_1}{x_2-x_1}\]
After finding the value of m, choose one of the point and plug in the values of it and m in y=mx+c to find c.
Does that help? @iribeiro1602

Answer 7

yes, sort of... but now you're finding the equation :)

so find the slope first! like how we did it last time :)

Answer 8

...OK just a sec...

Answer 9

so after you find the slope, you can narrow your choices down a bit :) and y=mx+b, the b part is the y-intercept, so afterwards, you just do what @ajprincess said, and find it and plug in! :) by substituting :)

Answer 10

I've got y= -0.5x - 2

Answer 11

That = y= -1/2x - 2

Answer 12

yup right:)

Answer 13

yup! that's right! :) cuz 0-(-2) / -4/0 = 2/-4= -1/2 which is your slope :)

and of those two values, the y values are 0 and -2, and of your choices, -2 is it!

so good job :)

Answer 14

well done:)

Answer 15

Thanks both!!!!!!!

Answer 16

Welcome:)