Coffee-cup calorimeter
When a 100.0 mL of 0.200 M NaOH solution is
mixed with a 100.0 mL of 0.200 M HCl solution
in a coffee-cup calorimeter, the temperature of
the solution increases from 25.00 oC to 26.35 oC.
Assuming that the specific heat of the solution is
4.184 J/(g oC) and that the calorimeter itself
absorbs a negligible amount of heat, calculate
the heat of the reaction (in kJ/mol) for the
neutralization reaction.

Question

Coffee-cup calorimeter
When a 100.0 mL of 0.200 M NaOH solution is
mixed with a 100.0 mL of 0.200 M HCl solution
in a coffee-cup calorimeter, the temperature of
the solution increases from 25.00 oC to 26.35 oC.
Assuming that the specific heat of the solution is
4.184 J/(g oC) and that the calorimeter itself
absorbs a negligible amount of heat, calculate
the heat of the reaction (in kJ/mol) for the
neutralization reaction.

aaronq · Answer

q=mCdT

solve for q

did they give you densities of the solutions?

anonymous · Answer

There is not density of the solutions. I learned to do q=mct  with no d.
There is 1g/ml density of the water. Which i think is absorbing the heat. Perphaps the heat gained by the water= heat lost by solutions. I also used the forumla H=U+NRT.
The anwser is supposed to be -56 kj/mole     but how do i get this?

aaronq · Answer

dT = delta T = (T2-T1)=  change in temperature

aaronq · Answer

try using the density of water for the solution, 200mL