Question

please helppp..What is the value of a for the following circle in general form? x^2+y^2+ax+by+c=0

Answer 1

http://media.apexlearning.com/Images/200706/04/9e57f591-82fc-4918-a258-21613b9226fd.jpg

Answer 2

you will need to complete the square for both x and y

general equation: \[x^{2} + ax = (x + a/2)^{2} - (a/2)^2\]

Answer 3

help...

Answer 4

lol ok. well that was for x.

\[y^{2} + bx = (y + b/2)^{2} - (b/2)^{2}\]

completing the square just gives an equivalent way of writing it. and the point of it is to put it in the general form of the circle.

Answer 5

so: \[(x +a/2)^{2} + (y + b/2)^{2} = (a/2)^{2} + (b/2)^{2}\]

Answer 6

yeah i think

Answer 7

r ^ 2 = [(a/2)^2 + (b/2)^2]

Answer 8

so how would i find the value of a

Answer 9

the final answer is 3 above

Answer 10

you can't, it's not given. the question was just to place it in the general form

Answer 11

my bad . i didn't see the c

Answer 12

so is the question like a bad question,it's asking for the value of a

Answer 13

final answer is : \[(x + a/2)^2 + (y + b/2)^2 = [(a/2)^2 + (b/2)^2 - c]\]

Answer 14

ugh this is so confusingggggggggggg i dont know what to type in

Answer 15

i'm not sure what they mean by value of a.

maybe by a they mean h. and the answer would be -a/2

Answer 16

or maybe a is the radius

Answer 17

i have no idea,i copy and pasted the equation

Answer 18

do they show this somewhere?

\[(x - a)^2 + (y - b)^2 =r^2\]
or do they use h and k ?

Answer 19

at the very top is all they show and the graph thaty's it]