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information is given about a polynomial f(x) whose coefficients are real numbers. Find the remaining zeros of f Degree 4; zeros: i, 14+i what are the remaining zeros of f
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for polynomial with degree 4 there will be totally 4 zeros. Now you are given two zeros that are complex. Both zeros are different. For polynomials with real coefficients if a+ib (Complex No.) is a zero then a-ib (its conjugate) is also a zero. So if 'i' is a zero then '-i' is a zero too. Similarly if '14 + i' is a zero then its conjugate '14-i' is also a zero.
So the zeros are\[i, -i, 14+i, 14-i\]
wow that seem easy now that it was sexplained
when entering the reaming zero it would just be -i and 14-i right
yes
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okay thank you!
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