find the sum of the sequence (look below)
\[\sum_{k=1}^{4} \left( k ^{3} +4\right)\]
write it out
put 1 for k, then 2, then 3 , then 4. Add all the answers together
wow it was that simple? looked more complex so the answer i got was 5, 12, 31, 68
how did you get 31?
and 68?
I just plug in 3 and 4 for k
and all I have to do is add them up right?
yeah, plug in 1,2,3,4. Add up the results. But, 31, 68 ain't part of the 'plug in results'
really? i got 31 from plugging in 3 and 68 by plugging in 4?
3^2 +4 = 9+4 = 13 or is it ^3 you wrote?
if it's k^3, then you're right..........couldn't see the power clearly....
yeah its ^3 so do I just add them all up for the sum
yeah. That's all.
thanks again!! You really are a big help!
yeah, you're very welcome.
you could also.post a testimonial for me.........(-_-)
Join our real-time social learning platform and learn together with your friends!