Question

(z-8) times (z-5)

Multiply the binomals.

Answer 1

FOIL away :)

Answer 2

What is the foil method?

Answer 3

Excellent question :)
When you multiply a pair of binomials, say, (a + b) and (c + d)

We have what are called its FIRST terms \[\large (\color{red}{a}+{b})(\color{red}{c}+{d})\]

Its OUTER terms \[\large (\color{green}{a}+{b})({c}+\color{green}{d})\]

Its INNER terms \[\large ({a}+\color{orange}{b})(\color{orange}{c}+{d})\]

And finally, the LAST terms. \[\large ({a}+\color{blue}{b})({c}+\color{blue}{d})\]

Answer 4

lol

Answer 5

That's what FOIL stands for, FIRST, OUTER, INNER, and LAST terms.

In your case, you have (z-8) and (z-5)

In this pair, what are your FIRST terms?

Answer 6

z & z?

Answer 7

z and z so z squared

Answer 8

That's right :)
So you multiply them, and you get?

Answer 9

... z^ 2?

Answer 10

the first part of the equation

Answer 11

Good. So put that down...
\[\Large \color{red}{x^2}...\]
Next... what are the OUTER terms?

Answer 12

z & 5 ?

Answer 13

-5z

Answer 14

Pay close attention to the signs... they matter :)

Answer 15

okay okay, i get it now. thank you.

Answer 16

Great :)
If you're willing, post your answer :D

Answer 17

-5z is wrong.

Answer 18

That's because that's not the answer, but only part of it.

Answer 19

ohhhhhhhhh.

Answer 20

You have to apply the whole of the rule

Answer 21

Use this!:D