Question

Use complete sentences to describe the steps taken to simplify this problem. Make sure you include information about the new common denominator, the final simplified expression, and any restrictions.
3/x + 3/x+ -3/x+2

Answer 1

Find the common denominator by multiplying x by x+2. The new common denominator will be x(x+2), and the resulting fraction is going to be:
[3(x+2)+3(x+2)-3x]/[x(x+2)]

Answer 2

are you sure your reading the problem right

Answer 3

its 3/x + 3/x- 3/x+2

Answer 4

Can you draw it or use parenthesis properly?

Answer 5

ok hold on

Answer 6

can i send you a picture

Answer 7

of it

Answer 8

yea attach a picture

Answer 9

ill just
send you link

Answer 10

ok ill attach it give me a secx

Answer 11

u there

Answer 12

Ok just post the correct question next time..
You wrote 3/x + 3/x- 3/x+2

It's actually 3/x + 3/(x+1) + 3/(x+2)

Answer 13

ok sry about that

Answer 14

So find the common denominator by multiplying all the denominators. The common denominator will be:
x*(x-1)*(x+2)

Answer 15

ok

Answer 16

Sorry i just realized that the question said: 3/x + 3/(x+1) - 3/(x+2). The first step will remain the same though.
Combine all the fractions under one common denominator:
[3(x+1)(x+2)+3x(x+2)-3x(x+1)]/[x(x+1)(x+2)]

Answer 17

ok

Answer 18

ok

Answer 19

ok whats the restrictions

Answer 20

Now simplify the numerator by expanding all the parenthesis:
[3(x+1)(x+2)+3x(x+2)-3x(x+1)]/[x(x+1)(x+2)] =
[3(x^2+2x+x+2x+x^2+2x-x^2-x)]/[x(x+1)(x+2)] =
[3(x^2+6x)]/[x(x+1)(x+2)]=
3x(x+6)/[x(x+1)(x+2)]

Answer 21

is this step 2

Answer 22

it's step 2 continued.

Answer 23

ok

Answer 24

continue plz

Answer 25

And finally simplify the fraction further by cancelling Xs in the numerator and the denominator to get:
(3x+18)/[(x+1)(x+2)]

Answer 26

ok whats the restrictions

Answer 27

The restrictions are as follows:
x cannot be negative one or negative two.

Answer 28

ok ty so much

Answer 29

can you heelp me with another 1

Answer 30

its easier