Question

Is sqrt(3)(cos(225 degrees) + isin(225 degrees)) the polar form of 3-3i?

Answer 1

\[\sqrt{3}(\cos(225 degrees) + i \sin(225 degrees))\]

Answer 2

how did you find the modulus?

Answer 3

Wait, I know what I did wrong. I thought it was modulus(r) = \[\sqrt{3^{2} - 3^{2}}\], but it's \[\sqrt{3^{2} + (-3)^{2}}\].

Answer 4

modulus is \(\sqrt{3^{2} + 3^{2}}\)

Answer 5

the question is not about finding anything other than \(\cos(225)\) and \(\sin(225)\)
then multiply

Answer 6

so \(\large \sqrt{18} = \sqrt{3^2 \times 2} \)

Answer 7

your \(tan(\theta) = \frac{3}{3} = 1\)

Answer 8

I thought \[\tan(\Theta) = (-3)/3\] since b = -3.

Answer 9

\(tan^{-1}{(1)} = 45^o\) on the I quadrant, because the "x" and "y" are both positive

Answer 10

ohh, yes... it's ... -3 shoot

Answer 11

That's fine, thanks for helping.

Answer 12

ok, then .. the modulus is the same (-3)^2 is 3 anyway, the angle will just be on the IV quaddrant, "x" is positive, "y" negative

Answer 13

I got 315 degrees in QIV.

Answer 14

yes