Question

even more sigma notations:

Answer 1

\[\sum_{i=12}^{27}-5+13i\]

Answer 2

@primeralph @waterineyes

Answer 3

same thing from 12 to 27

Answer 4

do i have to write it all out?
is there an easier way or no?

Answer 5

there are easier way.............but your professor might not want that

Answer 6

*ways

Answer 7

[-5+13(12)] etc. right?

Answer 8

Just take the common things out of it..

Answer 9

\[\sum_{a}^{b}[\alpha+\beta i]\]

\[=\alpha(b-a+1)+\beta\left(\frac{b(b+1)}{2}-\frac{(a-1)a}{2}\right)\]

Answer 10

[-5+13(12)]+[-5+13(13)]+[-5+13(14)]+[-5+13(15)]+[-5+13(16)]+ [-5+13(17)]+[-5+13(18)]+[-5+13(19)]+[-5+13(20)]+[-5+13(21)]+ [-5+13(22)]+[-5+13(23)]+ -5+13(24)]

Answer 11

You will get like:

16*(-5) + 1[12 + 13 + 14 + 15........]

Answer 12

well,,,,,,,,,,you get it

Answer 13

That is 13 not 1 with those [] brackets..

Answer 14

Otherwise, Zarkon has given you one formula, use it..

Even I write it on my notebook, I had not studied Sigma in my school much..

Answer 15

[-5(x156]+ [-5(169)]+ [-5(182)]+ [-5(195)]+ [-5(208)]+ [-5(221)]+ [-5(234)]+ [-5(247)]+ [-5(260)]+ [-5(273)]+ [-5(286)]+ [-5(299)]+ [-5(312)]

Answer 16

what calculator do you use?

Answer 17

apple calculator

Answer 18

ah...if you have a TI I could show you a way to do it on the calculator

Answer 19

ok sry,lol

Answer 20

you could also type

sum[-5+13i,i=12..27]

into wolfram alpha and get the answer

Answer 21

-780 -845 -910 -975 -1040 -1105 -1170
-1235 -1300 -1365 -1430 -1495 -1560

Answer 22

-15210

Answer 23

that's not one of the choices

Answer 24

i get it in wolfram alpha though