Ask your own question, for FREE!
Chemistry 14 Online
OpenStudy (anonymous):

How do you obtain pure iron from iron(iii) sulfate

OpenStudy (chmvijay):

just by reduction

OpenStudy (chmvijay):

is that you wanted or something more you need

OpenStudy (anonymous):

can u explain a little in detail like the chemicals needed to be added

sam (.sam.):

Electrolysis?

OpenStudy (chmvijay):

by single dispalcment reaction also he can do using proper metal :)

sam (.sam.):

\[2Fe+3CuSO_4 \rightleftharpoons 3Cu+Fe_2(SO_4)_3\]

OpenStudy (anonymous):

so by using electrolysis we can collect iron?

OpenStudy (chmvijay):

yaaa LOL you can :)

sam (.sam.):

Half reaction should be \[Fe^{3+}+3e^- \rightarrow Fe\]

sam (.sam.):

Cathode

OpenStudy (chmvijay):

and what is anode lol by the way

sam (.sam.):

\[Cu \rightarrow Cu^{2+}+2e^-\]

OpenStudy (chmvijay):

LOL Fe + CuSO4 ---->Cu +FeSO4

sam (.sam.):

@amstro yeah, from equation \[2Fe+3CuSO_4 \rightleftharpoons 3Cu+Fe_2(SO_4)_3\] --------------------------------------------------- Half reaction (Anode) \[Cu \rightarrow Cu^{2+}+2e^-\] --------------------------------------------------- Half reaction (Cathode) \[Fe^{3+}+3e^- \rightarrow Fe\] You'll see deposits of solid irons on the cathode

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!