A box contains 6 nuts, 8 bolts, and 4 screws. If 3 objects are selected in succession randomly, what is the probability of selecting a nut, then a bolt, then a screw, if replacement occurs each time?
overall probability is the product of the individual probabilities. take each draw separately. first you want a nut. that is 6/(6+8+4) then that nut is put back. you then want a bolt. that is 8/(6+8+4) then that bolt is put back. you finally want a screw. that is 4/(6+8+4) take each of those three probabilities and multiply them together and you'll have your answer.
i dont understand could you answer it for me. Math is my biggest weakness and i need this to graduate
total objects=6+8+4=18 reqd. probability=6/18 *8/18 *4/18 solve and you get the answer.
Sorry, i won't give the answers away. i am willing to help you figure it out, but i won't do the work for you.
thanks alot yall
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