In the diagram, the y-coordinate of each edge illustrates a cosine function. Write an equation for the y-coordinate of one edge. (Diagram attached)
the equation for a cosine function is y = A*cos(Bx) where A affects the amplitude (height of the wave) and B affects the period of the wave (the places it crosses the x-axis) The amplitude (highest and lowest values of the curve) of a regular cosine function is 1...which you have (the curve goes from -1 to 1) so A = 1. Normally, the curve will cross the x-axis at pi/2 and 3pi/2, but here it crosses at 6 and 18. So, to find B, we need to solve B(pi/2) = 6...multiply both sides by pi/2 and you'll have B. Your answer will be y = cos(Bx) where B is the answer you get from that solution...the other curve would be the same with a negative in front.
SO B = 9.42 ?
doesn't look right...best to leave it in terms of pi. B(pi/2) = 6 B = 6(2/pi) B = 12/pi You can check this against the 3pi/2...B(3pi/2) should equal 18 (3pi/2)(12/pi) = 36pi/2pi = 18 since the pis cancel top/bottom, and a 2 cancels top/bottom. makes sense?
Oh okay, yes, makes a lot more sense now!
The equation would be y = cos (12/pi) Correct?
Or is it y = cos (12/pi) x
\[y=\cos(\frac{ 12 }{ \pi }x)\]
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