Question

can someone write me oxidation and reduction of this equation: Cl2 + H2O --> HCl + HOCl

Answer 1

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I just wrote an entire explanation but then the page automatically reloaded so it's all gone :(
So i'll do it in steps now.

\(Cl_2+H_2O\rightarrow HCl+HOCl\)

Step 1: determination of oxidation states
\(\Rightarrow\) In what oxidation state are the atoms?
I already tell that the oxidation state of \(Cl_2~\&~O_2\) is 0 because they're in elemental state which means they cancel eachother out

Answer 2

I'll take a different approach:
Which atom is oxidized and which atom is reduced?

Answer 3

Cl2 is oxidized and O2 is reduced

Thank you for tryin to help me :)

Answer 4

uh sorry there is no O2 in the equation i got confused with something else.
You're correct about \(Cl_2\) being oxidized
Actually it's both oxidized and reduced.
Oxidation = Cl from \(Cl_2\) to \(Cl^+\) in HOCl
This because H = +1, O = -2, so Cl needs to be +1 so that the total is zero.
Reduction = Cl from \(Cl_2\) to \(Cl^-\) in HCl
This because H = +1, Cl needs to be -1

Answer 5

A redox reaction in which one substance is both oxidized and
reduced is called a disproportionation reaction by the way :D funfact

So in this case each half reaction starts with the same reactant

Answer 6

Haha interesting
Anyway, I didn't get it right
Oxidation should go something like this: Ox: Cl2 --> Cl+ + e- or? And reduction just oposite with minus?

Answer 7

You're right about the oxidation. Only 2 Cl produces 2 Cl- and 2 electrons. The reduction is the loss of electrons so the electron is on the other side

Answer 8

So the oxidation reaction is \(Cl_2 \rightarrow 2Cl^+ + 2e^-\)
Reduction is the same exept the electrons are now on the other side of the arrow: \(Cl_2 +2e^ -\rightarrow 2Cl^+ \)

Answer 9

If you want to write the equation the way i did you can use \(\LaTeX\).
for the oxidation reaction type:
`\(Cl_2 \rightarrow 2Cl^+ +2e^-\)`
It looks a lot better than plain text and people will understant your problem better (without confusions)

\(\Huge \tt \color{blue}{I~hope~this~helped!!!}\)
`\( \Huge \tt \color{blue}{I~hope~this~helped!!!} \)`

Answer 10

Haha thank you very much, I figured it out :)