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solve x-19 >(greater then equal to)23 x < (greater then equal to) 42 x >(greater then equal to) 42 x > (greater then equal to) 4 x < (greater then equal to)4
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how would you solve x-19 = 23? what would "x" be there?
4
well, you do the same, just for this specific, pretend the \(\large \ge\) is a =
so its x> greater then equal to 4
hmm, well, how did you get "4"?
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for one, say, x-19 = 23 (+19 both sides) to isolate "x" x= ?
its 42
:) so \(\arge x\ge 42\)
how do i know if it goes < or >
woopsie
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*<
so \(\large x\ge 42\)
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