Eliminate the parameter t. Find a rectangular equation for the plane curve defined by the parametric equations. x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π A. x^2 - y^2 = 6; -6 ≤ x ≤ 6 B. x^2 - y^2 = 36; -6 ≤ x ≤ 6 C. x^2 + y^2 = 6; -6 ≤ x ≤ 6 D. x^2 + y^2 = 36; -6 ≤ x ≤ 6
so, if x= 6cos(t), what would that make cos(t) = ?
ok, so if x = 6a, what would "a" be equal to? solving by "a" I'm assuming you know how to factor :|
c
so if x= 6a, a =c ? that's a new one, but ok
im saying the answer i choose it C
oh
well, we don't know, that's the reason why we're looking for the cos(t) :)
I don't think is what your teacher had in mind
once you solve it, thus you'd know
ok let me figure it out brb
since cos2(t)+sin2(t)=1 you have x2+y2=36 the answer is D x^2 + y^2 = 36; -6 ≤ x ≤ 6
yes :), and yes, is an ellipse, thus "x" moves about from -6 to 6, depending on what "t" gets
;-) yayy
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