Question

Need help...

Answer 1

any idea? I don't care whether it 's a good or bad, if it helps you, so apply.

Answer 2

@Loser66 Nope, i forgot about this

Answer 3

@jim_thompson5910

Answer 4

I good way is study how to get the answer. the bad way is substitute the answer one by one, and consider which one is the answer. pick one

Answer 5

@e.mccormick come here and help him ,please.

Answer 6

@Loser66 here's work for the problem, but i just don't know how to factor completely

Answer 7

Do you know how synthetic division works? The example shows it, but I mean do you understand what it is saying to do?

Answer 8

@e.mccormick yeah i kinda do know how synthetic division, its just that the question asks to factor completely

Answer 9

No problem. That is related to synthetic div. If there is no remainder, it is a factor! Also, that example is not the same as the problem. It is only similar.

Answer 10

@e.mccormick do you have an idea of what the answer would be?

Answer 11

@e.mccormick here's another answer but i dont know how to make it look like the answers choices

Answer 12

I know the process. I am trying to find out what problem you are having with the process.

Answer 13

Did you start with something like this?

Answer 14

@e.mccormick yes, this is the work

Answer 15

OK. The 0 there proves the -5 is a solution without a remainder, and therefore (x+5) is a factor. Now you just need to factor the other part, \(x^2-2x-3\)

Answer 16

@e.mccormick ok so this is the factored equation

Answer 17

Yes, that is the rest of it. So you have \((x+5)(x+1)(x-3)\) as the fully factored version of the original equation.

Answer 18

@e.mccormick so its A right?

Answer 19

Because your syntetic took the original and did this:, \(x^3 + 3x^2 -13x -15=(x+5)(x^2-2x-3)\)

Then you factored the second part:
\((x+5)(x^2-2x-3)=(x+5)(x+1)(x-3)\)

And yes, that is A.