Question

Find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to scale.

Answer 1

@RadEn

Answer 2

x^2 = 9 * (9+14)
solve for x

Answer 3

14.3?

Answer 4

yup

Answer 5

oh okay. could you help me with some more?

Answer 6

sure

Answer 7

Find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to scale.

Answer 8

x * 9 = 8 * 23
solve for x

Answer 9

20.4?

Answer 10

that's right

Answer 11

yay ok i got another one

Answer 12

Find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to scale.

AB = 18, BC = 8, and CD = 5

Answer 13

@RadEn

Answer 14

use the secant's theorem :
BC * AC = x * CD or
BC * (BC+AB) = x * CD

so,
8 * (8+18) = x * 5
solve for x

Answer 15

opsss, the equation above should
BC * AC = x * (x+CD) or
BC * (BC+AB) = x * (x+CD)

so,
8 * (8+18) = x * (x+5)
solve for x

Answer 16

x^2+5x=208?

Answer 17

yep, or it can be
x^2 + 5x - 208 = 0
use the quadratic formula :
x = (-b +- sqrt(b^2 - 4ac))/(2a)

Answer 18

ahh i dont know how to do that

Answer 19

damn... i make a big mistake, sorry --"
that should like this
(BC+AB) BC = (x+CD) CD
(8+18)8 = (x+5) 5
26 * 8 = 5x + 25
208 = 5x + 25
208 - 25 = 5x
183 = 5x
x = 183/5 = 36.6

Answer 20

ohhh okay i see now

Answer 21

Find the diameter of the circle for BC = 10 and DC = 23. Round to the nearest tenth.
The diagram is not drawn to scale.

Answer 22

@RadEn

Answer 23

10 (10 + x) = 23^2
solve for x
(i assumed the diameter of that circle is x)

Answer 24

52.9?

Answer 25

10 (10 + x) = 23^2
10 (10 + x) = 529
divide by 10 from both sides, giving us
10 (10 + x)/10 = 529/10
10+x = 52.9
subtracted 10 from both sides,
10+x-10 = 52.9 - 10
x = 42.9

Answer 26

yeah i had got 529 idk why i did that

Answer 27

hehe, just forgot about 10 beside x :P

Answer 28

Write the standard equation for the circle.

center (–6, 9), r = 3

Answer 29

yh lol

Answer 30

is (x + 6)2 + (y – 9)2 = 9 right?

Answer 31

use the formula :
(x-h)^2 + (y-k)^2 = r^2

with h,k is the centre of circle and r its radius
actually, becomes like yours
(x + 6)^2 + (y – 9)^2 = 9
good job :)

Answer 32

yayy

Answer 33

Find the center and radius of the circle with equation (x + 2)2 + (y + 10)2 = 4.

Answer 34

change to be :
(x - (-2))^2 + (y - (-10))^2 = 2^2
therefore the centre is (-2,-10) and its radius r = 2.

Answer 35

ohhh wow your really smart :)

Answer 36

What is the equation of the circle with center (3, 5) that passes through the point (–4, 10)?

Answer 37

u have to find the radius of that circle, first
use the standard form equation again :
(x-h)^2 + (y-k)^2 = r^2
now, plug (h,k) = (3,5) and x,y = (-4,10) to formula above :

(-4-3)^2 + (10-5)^2 = r^2
(-7)^2 + 5^2 = r^2
49 + 25 = r^2
so, r^2 = 74

Answer 38

subtitute back the value of r^2 = 74 to equation above, it is
(x-h)^2 + (y-k)^2 = r^2
(x-3)^2 + (y-5)^2 = 74

Answer 39

oh okay then so for this one What is the equation of the circle with center (0, 0) that passes through the point (5, –4)? the amswer would be x2 + y2 = 41?

Answer 40

yes, the standard formula the equation of circle with the centre (0,0) is
x^2 + y^2 = r^2
to get r^2 just subtitute the point given (5,-4), ending like yours :)

Answer 41

yaay im learning lol

Answer 42

A manufacturer is designing a two-wheeled cart that can maneuver through tight spaces. On one test model, the wheel placement (center) and radius is modeled by the equation (x + 2)2 + (y – 1)2 = 4. What is the graph that shows the position and radius of the wheels?

Answer 43

those are the choices

Answer 44

i will go the first one

Answer 45

oh okay yeah that was right

Answer 46

i need help with some more

Answer 47

can u post it in the new question, please
my laptop be hanging if there are to many pics :)

Answer 48

ok sure

Answer 49

thanks :)