an expression is shown below. which value of x makes the expression equivalent to 10 times the square root of 51? 2 times the square root of 51x
\[2\sqrt{51x} = 10\sqrt{51}\]Any ideas?
a) 5 b) 25 c) 50 d)100
\[10\sqrt{51} = 2\times 5\sqrt{51}\]And it's given that \(2\sqrt{51x} = 2\times 5\sqrt{51}\). Begin with cancelling \(2\) and \(\sqrt{51}\) from both sides. You are left with \(\sqrt{x} = 5\)
Do you get what I said?
Yes I do. thank you so much(:
So what do you get for the answer?
a...right?
How do you get that?
..uh yeah im lost Cx im not good with algebra. could you explain?
Can you first show what you tried at least?
I mean like, I don't know it. I don't know what to do at all. I just thought 5 was the answer..but I have no idea how to show the work
Did you understand what I did there...?
no
You earlier said you did. Erm
Keep reading it. You'll certainly have that "ah!" moment if you try to.
I have no clue what to do. Could you POSSIBLY explain it to me?
OK. Do you see how \(10\sqrt{51} = 2\times 5 \sqrt{51}\)?
Yes. That parts simple
And you want to solve the equation \(10\sqrt{51} = 2\sqrt{51x}\) right?
Yes.
So technically you are solving \(2 \times 5\sqrt{51} = 2\sqrt{51x}\). Got it?
yeah. but why does 51 stay the same?
Why wouldn't it?
I thought that since 51 is multiplied by x that it would change. but clearly it doesn't. i really do not know.
Umm, we're gonna proceed with stuff. But do you understand it till \(2\times 5\sqrt{51}=2\sqrt{51x}\)?
I don't understand why x cancels out. So no.
we haven't done any cancellations till now.
In the first part of the equation you just put, where is the x? I don't understand how it's equal to the second part.
Err... let's do that again. The question wants such a value of \(x\) in \(2\sqrt{51x}\) such that it equals \(10\sqrt{51}\). What would you do here?
Okay. Nevermind. I don't get it.. ill find help somewhere else.
If you want help, why not get it here?
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