Question

find the domain of the function square root of 6x-42

Answer 1

Find the restrictions of x, ie when \(\sqrt{-x}\)

Answer 2

\[\sqrt{6x-42}\]
Or just solve 6x-42=0
x=7
So if x is larger than 7, then we'll have all positive values

Answer 3

i understand that part i just dont know how to write the answer in correct form

Answer 4

x equal to 7 will work as well, it'll give \(\sqrt{0}\)

Answer 5

Write
\[\left\{ x \in \mathbb{R} : x \geq 7 \right\}\]

Answer 6

do i use brackets or parenthesis? and is it just (x> or = 7)

Answer 7

the true values of the range are considered to be b/w 0 and infinit (for which i wlii write only q)
so let the given func be y
0<y<q
0< (6x-42)^(1/2)< q
suqaring the iniquality
0< (6x- 42)< q
adding 42 and dividing by 6 the whole iniquility
42/6 < x < q
thus
7< x< q

Answer 8

so \[x \in [7,\infty)\]

Answer 9

Use { }