Determine for what numbers, if any, the given function is discontinuous.
f(x) =
A. 5
B. None
C. 0
D. -5, 5
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OpenStudy (anonymous):
OpenStudy (anonymous):
discontinuous at 5 since the function changes at that point. graphically, the limit approaching 5 from the left is different than the one from the right
OpenStudy (anonymous):
so the answer is 5
OpenStudy (anonymous):
yes. not -5
OpenStudy (anonymous):
ok cool thanks @Euler271
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OpenStudy (anonymous):
i have one more if you dont mind @Euler271
OpenStudy (anonymous):
Use properties of limits to find the indicated limit. It may be necessary to rewrite an expression before limit properties can be applied.
A. 16
B. does not exist
C. -16
D. 0
OpenStudy (anonymous):
OpenStudy (anonymous):
you need to apply l'Hopitals rule which states that.
\[\lim_{x->a} \frac{ f(x) }{ g(x) } = \lim_{x->a} \frac{ f'(x) }{ g'(x) }\]
this is used when the limit the first time around gives 0/0 or inf/inf
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
what do you do next
OpenStudy (anonymous):
you would do plug in x = 1 again.
so taking f'(x)/g'(x) gives:
\[\lim_{x->1}\frac{ 3x^2 + 10x + 3 }{ 1 } = 16\]
OpenStudy (anonymous):
thank so so so so much for all your help @Euler271 I truly appreciate it ;-)