Find the x-intercept(s) and the coordinates of the vertex for the parabola y=x^2-2x-35 . If there is more than one x-intercept, separate them with commas.

Question

Find the x-intercept(s) and the coordinates of the vertex for the parabola y=x^2-2x-35  . If there is more than one x-intercept, separate them with commas.

anonymous · Answer

attachment

johnweldon1993 · Answer

Well the x-intercept(s) will come when you find the 'zeros' of the equation..

You've heard of the quadratic formula correct?

anonymous · Answer

right

johnweldon1993 · Answer

So use the quadratic formula to solve for your x-intercept(s) first...what do you get?

compassionate · Answer

y = 1x^2 - 2x - 35

b^2 = -4(a)(c) 
= (-2)^2 - 4(1)(-35)  = 144

There are 2 real solutions. 

1 +/6 sqrt[1] <-- Now if I do 

1 + 6 [1] 
1 + 6 
x = 7 

Now I do 

1 - 6 = ?

johnweldon1993 · Answer

And to solve for the vertex you just use

$$\frac{ -b }{ 2a }$$

where again 'b' is your 2nd coefficient and 'a' is the first...this will give you the x coordinate of the vertex...to find the y coordinate of the vertex....you plug what you just got for x....into the original equation for all x's...and see what you get for y

anonymous · Answer

i got for the vertex (1,-36) am I right?

anonymous · Answer

Compassionate are you using an example?

compassionate · Answer

x = 7
x = -5 

Now do find the vertex use the equation he gave you. Do some work on your own, we're not here to forcefeed you.