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First balance the equation
Now you have the ratio. 2 moles Fe reacts with 6 mol HCl. So the amount of moles Fe times 3 is the amount of moles HCl. When you multiply 9.8 by 3 you get 29.4 (this is the amount of HCl that can react with 9.8 mol Fe. This is way more than 11.5. When you divide 11.5 by 3 you get 3.8 (the amount of moles Fe that react with 11.5 mol HCl). so you now know that Fe is in excess so HCl is the limiting factor. According to the ratio, 6 mol HCl produces 3 mol H2. What's 11.5/2?
Yes that's amount of hydrogen produced with 11.5 mol hydrochloric acid in this reaction
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