Question

@jim_thompson5910

Answer 1

what is the area of the smaller rectangle

you can leave the area in factored form if you want

Answer 2

what do i have to do ? x * x + 2 ?

Answer 3

actually x * (x+2) and you can leave it factored like that for now

Answer 4

how about the larger rectangle

Answer 5

2x * x^2 + 5x + 6 ?

Answer 6

you need parenthesis, so it's 2x(x^2 + 5x + 6)

Answer 7

now factor x^2 + 5x + 6

Answer 8

(x + 2) (x + 3)

Answer 9

When you divide the smaller area by the larger, you get


\[\large \frac{x(x+2)}{2x(x^2+5x+6)}\]


which becomes


\[\large \frac{x(x+2)}{2x(x+2)(x+3)}\]


after you factor

Answer 10

what cancels?

Answer 11

(x + 2)

Answer 12

what else

Answer 13

the X ? lol

Answer 14

so that means

\[\large \frac{x(x+2)}{2x(x+2)(x+3)}\]

turns into

\[\large \frac{1}{2(x+3)}\]

Answer 15

after you do all the cancellations

Answer 16

got it thank you! :p

Answer 17

yw