Question

Which of the following is equivalent to 48xy2 + 24xy4 − 12x2y4?

12xy2(4 + 2y2 − xy2)

12xy2(4 − 2y2 + xy2)

12xy2(3 + 2y2 − xy2)

12xy2(4 − 3y2 − xy2)

Answer 1

@jim_thompson5910 @ganeshie8

Answer 2

what can you factor out of your equation?
12xy^2? then what do you have left?

Answer 3

Well all the problems seem to factor a 12xy^2, try doing that and see what you get

Answer 4

what would shakira do

Answer 5

always ask yourself this question

Answer 6

how can you factor 48 where one of the factors is 12

Answer 7

in other words, what is the solution to the equation 48 = 12x

Answer 8

it is a just take 12xy2 common from it

Answer 9

x = 4

Answer 10

so 48 = 12*4

Answer 11

yes

Answer 12

this means that if you had something like 48x + 12y, you can write it like this

48x + 12y

12*4x + 12*1y

12(4x + 1y) ... use the distributive property to factor out 12

12(4x + y)

Answer 13

or if you had something like this 48x + 36y, you can do this

48x + 36y

12*4x + 12*3y

12(4x + 3y)

Answer 14

ok :)

Answer 15

tell me what you get when you factor the original expression up at the top

Answer 16

factor as in foil or ...

Answer 17

factor as in use the distributive property

Answer 18

48x + 2y

Answer 19

you're on the right track, but you are a bit off

Answer 20

how ?

Answer 21

you have 48xy^2

how can you factor this so 12xy^2 is one factor

Answer 22

ummm idk ;/

Answer 23

well 48 factors to 12*4 right?

Answer 24

yes ..... and 6 * 2 factors to 12 (if u needed that) lol

Answer 25

yes we'll need that as well

Answer 26

but basically what I'm trying to get at is that 48xy^2 factors to 4*12xy^2 = (12xy^2)*4

Answer 27

ohhhhhhh ok !!!!!! i guess i need the baby words like how many times does 12 go into 48 lol xD

Answer 28

that's ok, approach it the best way for you

Answer 29

how would we factor 24xy^4 where 12xy^2 is one factor

Answer 30

dividing ? hold on what r u trying to ask me ? :p

Answer 31

yes in a way you will divide

basically I want you to solve for p in the equation

24xy^4 = p*12xy^2

Answer 32

what times 12 is 24 ? thats what ur trying to say ?

Answer 33

yes

along with the question "what times xy^2 gives me xy^4"

Answer 34

4y^2 ?

Answer 35

very good 4y^2 times 12xy^2 gives 48xy^4

Answer 36

oops I was looking at the wrong piece

Answer 37

it should be 2y^2

so

24xy^4 = 2y^2*12xy^2

Answer 38

see how I'm getting this?

Answer 39

ohh idk where i got 4 from if 12 * 2 = 24 lol yes

Answer 40

finally,

12x^2y^4 = q*12xy^2

what goes in place of q?

Answer 41

xy^2 ?

Answer 42

good

Answer 43

you're getting the hang of this

Answer 44

yaay

Answer 45

48xy^2 + 24xy^4 − 12x^2y^4

turns into

4*12xy^2 + 2y^2*12xy^2 - xy^2*12xy^2

then you factor out the common term 12xy^2 to get what?

Answer 46

4 + 2y2 - xy^2

Answer 47

you got it, you basically erase all the copies of 12xy^2 to get 4+2y^2-xy^2

then you write all that in a set of parenthesis with 12xy^2 sitting out front like this

12xy^2( 4+2y^2-xy^2)