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Mathematics 19 Online
OpenStudy (anonymous):

(x+1)^1/2 +(2x-5)^1/2 = 3 Plz solve as fast as possible and reply soon. I have a test on Quadratics tommorow

OpenStudy (anonymous):

@rajee_sam

OpenStudy (anonymous):

@AravindG @Emily778 @Frostbite @grayp @help123please.

OpenStudy (anonymous):

I'm not going to help you if your just gonna spam me. Sorry, but no thanks.

OpenStudy (dumbcow):

i would move one of the radicals to other side of equal sign then square both sides

OpenStudy (dumbcow):

oh are you a spammer :{ haha yeah only ask once is best policy

OpenStudy (rajee_sam):

my equations is not working

OpenStudy (dumbcow):

after squaring both sides isolate remaining radical to one side then square both sides again @rajee_sam , try refreshing browser a couple times

OpenStudy (dumbcow):

you will then have a quadratic equation set equal to 0 factor or use quadratic formula to solve ... good luck try to follow those steps

OpenStudy (rajee_sam):

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OpenStudy (rajee_sam):

sorry I missed the 6 in 2 of the steps

OpenStudy (rajee_sam):

|dw:1369589896655:dw|

OpenStudy (anonymous):

@rajee_sam I am not able to solve ahead, i have tried this question 20 times but i am not able to solve, kindly tell me each step, i have to solve 50 more of this type, so i will learn it if once you solve it completely

OpenStudy (dumbcow):

if all you want is the solution, there are other ways http://www.wolframalpha.com/input/?i=sqrt%28x%2B1%29+%2Bsqrt%282x-5%29+%3D+3 it will even give you step-by-step if you register with the site

OpenStudy (rajee_sam):

you see radicals in your equation. If you see one radical keep it on one side of the equation and take everything else to the other side eg. √ (x+ 1) - 3 = 15 keep the radical on the LHS and take the -3 to the RHS Now you will have √ (x + 1) = 15 + 3 = 18 Now you square both sides and you can solve for x But if you have two radicals like it is in our problem. Keep one radical on each side like I did. And keep squaring and combining like terms until you are left with no radicals. Now in our problem the last step I wrote was (x + 3)² = 36 ( 2x -5) right??

OpenStudy (anonymous):

yes, right....please progress...

OpenStudy (rajee_sam):

now you have to expand the LHS and expand the RHS of the equation you will have x² + 6x + 9 = 72x - 180 now again combine like terms x² - 66x - 171 = 0 now this is a quadratic equation which you can solve using quadratic formula. You know quadratic formula right??

OpenStudy (anonymous):

when you take -180 to the other side you will have to add +9 to +180, the solution is 3 and it isnt derived by this....

OpenStudy (anonymous):

@rajee_sam

OpenStudy (rajee_sam):

my bad yes

OpenStudy (rajee_sam):

so it will be x² - 66x + 189 = 0

OpenStudy (anonymous):

yes i got the answer, thanks....but there is definately a shortcut method to do this whc is really helpful with regard to competitive exams...anyways basics always work the best...thank you!! @rajee_sam

OpenStudy (rajee_sam):

( x - 63) ( x-3) will be your factors So your solutions are x = 63 , 3 Now you have to check for extraneous solutions by substituting these values in your original equation. you will find only x = 3 satisfies the equation and 63 I an extraneous solution.

OpenStudy (rajee_sam):

If you find the shortcut pl. teach me too

OpenStudy (anonymous):

alright i got it! @rajee_sam thanks for answering it as a whole...i am sorry if i did not follow any ideal of "Openstudy" but i got it!! Definately if i get a shortcut, i will put it on this post itself with your tag....thanks again! have a good day/night....

OpenStudy (dumbcow):

i believe the shortcut is to say what 2 integers add up to 3 0+3 or 1+2 0+3 will not work assuming 1+2 x+1 = 1 or 4 x+1 = 4 --> x=3 2(3) -5 = 1 sqrt4 + sqrt1 = 3 done

OpenStudy (anonymous):

@dumbcow thanks man! that was good.....i have already given a medal but i would also give this post a medal anyway informally....thanks!

OpenStudy (anonymous):

@rajee_sam hey @dumbcow has put a shortcut, its good we can use this approach...

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