Question

Express the complex number in trigonometric form. -6+6 sqrt(3)i

Answer 1

somebody please help me

Answer 2

gimme one sec, have you found the modulus yet? do you even know what that is?

Answer 3

the first number i think is 12

Answer 4

these are the answers

Answer 5

ahemm, one sec

Answer 6

http://mhanswers-auth.mhhe.com/sites/default/files/images/57%20polar.JPG

the "r" part is the so-called "modulus", as you can see from the picture is \(\large \sqrt{a^2+b^2}\)

Answer 7

oh i see

Answer 8

as as you can see from the picture, they way you get the "angle" is by using the tangent function

Answer 9

well i need help finding the moduous

Answer 10

well, just use => \(\large \sqrt{a^2+b^2}\)

Answer 11

from the a+bi complex expression

Answer 12

sqrt((-6)^2+(6 sqrt(3)i)^2 )

Answer 13

right, what does that give you?

Answer 14

$$
r=\sqrt{6^2+(6\sqrt{3})^2} \implies \sqrt{36+36(\sqrt{3})^2} \implies \sqrt{36+36(3)}
$$

Answer 15

so, what would that give you?

Answer 16

i really help guys

Answer 17

Just use De'Moivre's Theorem.

Answer 18

ok but how do you find the answer

Answer 19

these are the answers

Answer 20

please help me