Question

plse answer this question.................


three vertices of a square are P(-1,-9) , Q(3,-1) and R(-5,3) . plot these points on graph . and find the coordinate of missing vertex......

Answer 1

why are YOU asking this question???

Answer 2

i forgot how to find the missing (fourth ) vertex

Answer 3

It is a square (in spite of what it looks like lol) and all sides are equal in lenght and the corners are right angles (the lines are perpendicular)

Answer 4

hmm, i got the same figure

Answer 5

I would first find the slope of the line RQ.
delta y over delta x, giving us 4/-8 = -1/2 we know that line SP has to be parallel so the slope for that line is also -1/2. Then the equation for that line SP is

(y + 9)/(x + 1) = -1/2 y= -(1/2)x - 19/2 Now calculate the equation for the line RS
slope = 8/4 = 2, line equation is: y = 2x + 13

You now have a system of equations, 2 equations, 2 unknowns.

y= -(1/2)x - 19/2
y= 2x + 13 y=y -(1/2x)-19/2 =2x +13 multiply thru by 2
-x-19=4x + 26
-5x = 45
x=-9
y=2(-9) +13
y=-5
The 4th vertice is located at (-9, -5)

Answer 6

@radar
thanks bro

Answer 7

You are welcome, there are I'm sure many other ways to have found that, like using the distance formula etc., but I went that way.

Answer 8

Good luck in your studies, I will sign off for now.