Start with the point A (3, 1). Translate the point 1 unit to the left and 4 units down. What are the new coordinates of the point A’? Now translate A’ 3 unit to the left and 2 units up. What are the new coordinates of the point A’’? What translation would need to be made in order for the result to be the original point A (3, 1)?
This is an easy question, just count and move by the coordinates.
Translating is moving. Move by the units to the left they ask you to.
i did that.. i just need help with the last part.. "What translation would need to be made in order for the result to be the original point A (3, 1)?"
would it be move it to the right 4 and up 1?
First, where exactly did the point end up, after the first two translations?
its in the picture.. (-1,-1)
I just now saw that, lol ^.^ -1 , -1 So.. our original point was 3,1 Let's be clear, what happens in the left coordinate, stays in the left coordinate, same goes for the right. The key to this question is something that resembles vector addition (subtraction) If any of that is alien to you, then, just do this operation... <3 , 1> - <-1 , -1>
Confused? <a , b> - <c , d> = <a-c , b-d>
all of the that was alien to me.. I'm in online classes and havent gotten that far yet.. would it be move it to the right 4 and up 1?
A'=(2,-3) A"=(-1,-1) In order to get to the original point you would have to translate it 4 units to the right and 2 units up. is this correct?
Okay... we'll get to that later. By the way, in your drawing, you labelled (-1 , -1) as (-1 , 1) When you're looking for the translation that would send (-1 , -1) to (3 , 1) Let's call (3 , 1) our destination and call (-1 , -1) our origin. Take the left-coordinate of the origin, -1, and subtract it from 3, what do you get?
(We subtract -1 from 3, as it is the left-coordinate of the destination)
@rajee_sam There are two translations.
ty for pointing that out
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