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Chemistry 21 Online
OpenStudy (anonymous):

Please help:)

OpenStudy (anonymous):

http://screencast.com/t/GkMwABandaKj

OpenStudy (anonymous):

@Callisto @.Sam.

sam (.sam.):

You have to find which is limiting reagent, which one do you think it is?

OpenStudy (anonymous):

ethanoic acid

OpenStudy (anonymous):

50% s t

sam (.sam.):

Ok, we have 0.25moles of CH3COOCH2CH3 for 22g From what we've calculated, 0.5moles of CH3COOH in 30g, and also, n(CH3COOH)=n(CH3COOCH2CH3) 0.5=0.25 \[\% ~yield=\frac{0.25}{0.5} \times 100=50 \%\]

OpenStudy (anonymous):

thanks :)

sam (.sam.):

yw :)

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