Question

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Answer 1

A right triangle has a hypotenuse of length 15 and a leg of length 8. What is the area of the triangle? If necessary, round your answer to two decimal places.

Answer 2

Such a weird 'question'

Answer 3

srry man im studying for finals

Answer 4

Yeah, well, okay...
the area of a right triangle is half the product of its legs.
You already have one leg, 8
So how to find the other leg?

Answer 5

I got it... What is the area of ABC below? If necessary, round your answer to two decimal places.

Answer 6

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Answer 7

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Answer 8

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Answer 9

I always get the ............

Answer 10

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Answer 11

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Answer 12

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This will take a couple steps to solve. First, let's find the length of the base of the triangle with the following formula: A^2+B^2=C^2
"A" will represent one leg of the triangle and "C" will be the diagonal. Plug in the numbers:
8^2+B^2=15^2 Do the calculations:
64+B^2=225Subtract 64 from both sides to get:
B^2=161 Now square root both sides to result in:
B=12.69 (Rounded off)

Now we take the area of a Triangle which is:
Area=1/2Base*height
Plug in the numbers.
A=1/2(12.69)(8) Do the calculations.
A=50.76 square units.
Make sense?


This is How you solve question one. BTW.