Write the equation of the circle whose center is at the origin and whose diameter is 12.

Question

tkhunny · Answer

Well, do it!  What's your best guess?

anonymous · Answer

D = Pi R(sqd)
12 = Pi (6^2)
12 = Pi (36)
12/36 = Pi
1/3 = Pi

tkhunny · Answer

?? @nfgallimore  What?

Diameter is 12.  What is the Radius?

anonymous · Answer

diameter is 12, so radius would be 6 right? So maybe x^2+y^2=blank, I know it is less than 4 but more than three I think.

tkhunny · Answer

You have it.  "blank" is $r^{2} = 36$

anonymous · Answer

so how would this formula work out though? Would it come out like x^2+y^2=36?

tkhunny · Answer

That's it!!  Why do you doubt?

anonymous · Answer

haha, because I'm not the best at geometry xD thank you!!

tkhunny · Answer

Well, there you go.  Now you're a little bit better.  Hang in there!