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If h(x)=x^2-5, find h(-3) A.-14 B.-11 C.4
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plug -3 into h(x) to get ur answer
f(-3)=(-3)^2-5
I dont understand how to do the problem
"h(-3)" means "h of -3" (not "h times -3"), meaning the function h evaluated at x=-3. So you take h(x) and replace x with -3: h(-3) = (-3)^2-5 = 9 - 5 = ... Do you see?
Oh ok thank you. c:
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