Question

A parallelogram is drawn with a 60 degree angle as marked. Find the height of the parallelogram.

Answer 1

With this, we can use the SOHCAHTOA property, particularly SOH. SOH says you take \[\sin 60 \deg = \frac{ opp }{ hyp }\] in this case it's \[\sin 60=\frac{h}{3}\] solving for h \[h= 3*(\sin(60))\] i'll let you simplify that and get your answer :)

Answer 2

thank you! You see, I tried to look this up and study it but I honestly never heard of the "sin"

Answer 3

Or the SOH property

Answer 4

sine* there is Sine, cosine, tangent.

check this out :) http://www.mathwords.com/s/sohcahtoa.htm it'll teach you about SOHCAHTOA

Answer 5

alternative :
use the proportion sides of 30-60-90 right triangle :
1 : sqrt(3) : 2

Answer 6

how did you get a square root from 30-60-90? @RadEn

Answer 7

@RadEn how did you get 30?

Answer 8

someone please explain how to do this the alt way

Answer 9

a 30-60-90 triangle is represented as

Answer 10

you are given and you would use the Pythagorean Theorem \[\large y=a^2+b^2+c^2\] to solve .