Question

Help again! @jim_thompson5910

Answer 1

Solve the equation
\[\frac{ 1 }{ 3x+9 } - \frac{ 2 }{ x+3 }=2\]

Answer 2

Answer choices:
A. X=1
B. x=\[\frac{ -23 }{ 6 }\]
C. x=\[\frac{ -5 }{ 2 }\]
D. x=-5

Answer 3

\[\large \frac{ 1 }{ 3x+9 } - \frac{ 2 }{ x+3 }=2\]

\[\large \frac{ 1 }{ 3(x+3) } - \frac{ 2 }{ x+3 }=2\]

\[\large \frac{ 1 }{ 3(x+3) } - \frac{ 3*2 }{ 3(x+3) }=2\]

\[\large \frac{ 1 }{ 3(x+3) } - \frac{ 6 }{ 3(x+3) }=2\]

I'll let you finish

Answer 4

you can't subtract unless the denominators are the same

Answer 5

OK. So it would be -5 or D! Thanks again. @jim_thompson5910

Answer 6

no

Answer 7

I'll finish up

Answer 8

\[\large \frac{ 1 }{ 3(x+3) } - \frac{ 6 }{ 3(x+3) }=2\]

\[\large \frac{ 1 - 6 }{ 3(x+3) }=2\]

\[\large \frac{ -5 }{ 3(x+3) }=2\]

\[\large -5 =2*3(x+3)\]

\[\large -5 =6x+18\]

\[\large -5-18 =6x\]

\[\large -23 =6x\]

\[\large x = -\frac{23}{6}\]

Answer 9

That could have been bad! Thank you!

Answer 10

np

Answer 11

make sure you check any/all answers you get because sometimes with rational equations, possible solutions aren't really solutions at all

Answer 12

in this case, x = -23/6 is actually a solution, but checking is always good