Finish writing the equation of the line y = 1/4x + ? , given the points (-12, 0) and (4, 4). Type only the number that is missing after the final + or - sign.
This is solvable with the point-slope form of the equation for a line: y - y1 = m(x - x1) y - 4 = (1/4)(x - 4) y - 4 = (1/4)x - 1 y = (1/4)x + 3
The last equation is in slope intercept and the number is : 3
The slope was already given as 1/4, but also could have been calculated: (y2 - y1)/(x2 - x1) = m (4 - 0)/[4 - (-12)] = 4/16 = 1/4
in the equation \(y = (1/4) x + ....\), only one info is missing. Only one point is needed to find this value. As tcaroll010 said, it is 3. Replace y by 4 and x by 4 (we use (4,4)) and the equation must be ok. this will give you the value of "?" .
btw, that "3" is the y-intercept and the line looks like:|dw:1369870779060:dw|
So 1/4?
No, "3"
"3" is the # you want. "1/4" is just additional incidental information.
okay! so 1/4 x 3?
No, just "3"
3 goes where that ? is
oh
ok my error
my mistake - wow
np. Your question was basically to replace the "?" in: y = 1/4x + ? So, you get: y = 1/4x + 3
\(y = (1/4)x + p\). you want to find \(p\). If (4,4) is on the line, then the equation is satisfied at this point. So the equation \(4 = (1/4)4 + p\) is correct. This shows that \(p=3\).
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