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Algebra 18 Online
OpenStudy (anonymous):

Help please!!!

OpenStudy (anonymous):

With?

OpenStudy (anonymous):

No, sorry. The fact that it IS an identity makes it a bit difficult to verify any other way.

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

@tcarroll010

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

I can do this, hold on, @lala2

OpenStudy (anonymous):

ok :)

OpenStudy (anonymous):

\[1 + \frac{ \cos ^{2}\theta }{ \sin ^{2}\theta } = \frac{ 1 }{ \sin ^{2}\theta }\]\[\frac{ \sin ^{2}\theta + \cos ^{2}\theta }{ \sin ^{2}\theta } = \frac{ 1 }{ \sin ^{2}\theta }\]

OpenStudy (anonymous):

The first equation shows the left side = right side The second equation shows the left side. What I did was show that the left side equals the right side.

OpenStudy (anonymous):

oh ok!

OpenStudy (anonymous):

In other words, I showed that: 1/sin^2 = 1/sin^2

OpenStudy (anonymous):

thats clear!

OpenStudy (anonymous):

All good now? I gotta go eat! @lala2

OpenStudy (anonymous):

yeah! Thanks!:)

OpenStudy (anonymous):

im no longer typing have no idea why it says that!

OpenStudy (anonymous):

Good luck to you in all of your studies, and thx for the recognition! @lala2

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

uw!

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