Question

Solve this equation on the interval [0,2π)
2cos(x/2)-√3=0
Help please & Thank you!!!

Answer 1

start with
\[\cos(\frac{x}{2})=\frac{\sqrt3}{2}\]
then solve for \(\frac{x}{2}\) then double to solve for \(x\)

Answer 2

ok. gotcha! thank you so much! i appreciate it!

Answer 3

am i supposed to end up with :
cos=2√3/2x ???

Answer 4

heck no

Answer 5

my bad...

Answer 6

where do i go from where you told me?

Answer 7

you are supposed to get \(\frac{x}{2}=\frac{\pi}{6}\)

Answer 8

since
\[\cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}\]

Answer 9

hold up, where did the pi come from?

Answer 10

you working in degrees or radians?

Answer 11

the question does not specify..

Answer 12

if you are working in degrees, then since
\[\cos(30)=\frac{\sqrt3}{2}\]you get
\[\frac{x}{2}=30\iff x=60\]

Answer 13

ohhhh, i THINK i got it! thank you so much!