Help!?!?!? The equation y = 7 cos((pi/3)t) models the height h in centimeters after t seconds of a weight attached to the end of a spring that has been stretched and then released. a. Solve equation for t. b. Find the times at which the weight is first at a height of 1 cm, of 3 cm, and of 5 cm above the rest position. Round your answers to the nearest hundredth. c. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time. Round your answers to the nearest hundredth. (I already have A and B, i just have a question
For c, wouldnt the results be the same as b? What do i do differently on C? Do i just make 1, 3, and 5 negative or is it not that simple?
for C you find the period of the sine wave. the 2nd time it'll reach those heights = 1st time + time period.
Can you show me? I still dont really get it. (Im not good at math at all!) :(
ok, time period of a sine wave y=A cos (wt) is T = 2pi/w here w=pi/3, right ? so, T = 2pi/(pi/3) = 6 sec so, 2nd time the height will be 2cm at 1.36+6 = 7.36 sec. got this ?
yes.
Oh ok. I get it now. Thanks!!! :)
welcome ^_^
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